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Revision 12

Added by over 7 years ago

latest version of the ooas compiler, with grammar version 1.10

View differences:

OoaPrologExpression.java
53 53 
import org.momut.ooas.ast.identifiers.IdentifierKind;
54 54 
import org.momut.ooas.ast.types.EnumType;
55 55 
import org.momut.ooas.ast.types.FunctionType;
56 
import org.momut.ooas.ast.types.MetaType;
56 57 
import org.momut.ooas.ast.types.TypeKind;
57 58 
import org.momut.ooas.ast.types.Type;
58 59 
import org.momut.ooas.ast.types.ValuedEnumType;
......
282 283 
	@Override
283 284 
	public void visit(TypeExpression typeExpression)
284 285 
	{
285 
		if (typeExpression.type().kind() != TypeKind.EnumeratedType)
286 
		if (typeExpression.referredType().kind() != TypeKind.EnumeratedType)
286 287 
		{
287 
			m_emitter.Append(GetIdentifierString(typeExpression.type().identifier()));
288 
			m_emitter.Append(GetIdentifierString(typeExpression.referredType().identifier()));
288 289 
		}
289 290 
	}
290 291 

  		




  ......




  411
  412
  
    
	@Override


  		




  412
  413
  
    
	public void visit(AccessExpression accessExpression)


  		




  413
  414
  
    
	{


  		




  414
  
  
    
		if (accessExpression.left().type().kind() != TypeKind.EnumeratedType &&


  		




  
  415
  
    
		if (!(accessExpression.left().type().kind() == TypeKind.MetaType && ((MetaType)accessExpression.left().type()).Type().kind() == TypeKind.EnumeratedType ) &&


  		




  415
  416
  
    
		    !(accessExpression.right().kind() == ExpressionKind.Identifier &&


  		




  416
  417
  
    
		    ((IdentifierExpression)accessExpression.right()).identifier().kind() == IdentifierKind.AttributeIdentifier))


  		




  417
  418
  
    
		{


  		












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